помогите решить уравнения
a) (327x-5295)÷57=389;
b) (27y+11)×315=111970
a) (327x-5295)÷57=389;
b) (27y+11)×315=111970
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327х - 5295 = 389 * 57
327х - 5295 = 22173
327х = 22173 + 5295
327х = 27468
х = 27468 / 327
х = 84
(27y + 11) * 315 = 11970
27у + 11 = 11970 / 315
27у + 11 = 38
27у = 38 - 11
27у = 27
у = 27/ 27
у = 1