Помогите решить уравнения : (тема многочлены)
1) 28-(1-4x-x^2)=x^2-6x+8
2) 10-(2x^2+5x)-(7x-2x^2)=0
1) 28-(1-4x-x^2)=x^2-6x+8
2) 10-(2x^2+5x)-(7x-2x^2)=0
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Ответ:
1) 28-(1-4x-x²)=x²-6x+8.
28-1+4x+x²-x²+6x-8=0.
10x+19=0.
10x=-19.
x=-1,9.
2) 10-(2x²+5x)-(7x-2x²)=0.
10-2x²-5x-7x+2x²=0.
-12x+10=0.
-12x=-10.
x=10/12=⅚.