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mariammessi9
@mariammessi9
June 2022
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kirichekov
Verified answer
Log₃(3x²)*log₃(x³/9)=20
ОДЗ: x>0
log₃(3*x²)=log₃3+log₃x²=1+2*log₃x
log₃(x³/9)=log₃x³-log₃9=3log₃x-2
(1+2log₃x)*(3log₃x-2)=20
3log₃x+6*(log₃x)²-2-4log₃x=20
6*(log₃x)²-log₃x-22=0 логарифмическое квадратное уравнение. замена переменных:
log₃x=t
6t²-t-22=0
D=529
t₁=-22/12, t₁=-11/6
t₂=2
обратная замена:
t₁=-11/6, log₃x=-11/6, x=3⁻¹¹/⁶,
x₁=1/(⁶√3¹¹)
t₂=2, log₃x=2, x=3²,
x₂=9
1 votes
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mariammessi9
спасибо большое ☺
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Answers & Comments
Verified answer
Log₃(3x²)*log₃(x³/9)=20ОДЗ: x>0
log₃(3*x²)=log₃3+log₃x²=1+2*log₃x
log₃(x³/9)=log₃x³-log₃9=3log₃x-2
(1+2log₃x)*(3log₃x-2)=20
3log₃x+6*(log₃x)²-2-4log₃x=20
6*(log₃x)²-log₃x-22=0 логарифмическое квадратное уравнение. замена переменных:
log₃x=t
6t²-t-22=0
D=529
t₁=-22/12, t₁=-11/6
t₂=2
обратная замена:
t₁=-11/6, log₃x=-11/6, x=3⁻¹¹/⁶, x₁=1/(⁶√3¹¹)
t₂=2, log₃x=2, x=3², x₂=9