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Alexander270
@Alexander270
July 2022
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Помогите решить все номера
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petyaGavrikov
Verified answer
1.
100(10) = 1100100(2), 350(10) = 101011110(2), 70(10) = 1000110(2)
Решение - в прилагаемом файле.
2.
111(2) = 1*2^2+1*2^1+1*2^0 = 4+2+1 = 7(10)
203(4) = 2*4^2+0*4^1+3*4^0 = 32+3 = 35(10)
150(7) = 1*7^2+5*7^1+0*7^0 = 49+5*7 = 84(10)
3.
101010(2) = 1*2^5+1*2^3+1*2^1 = 32+8+2 = 42(10)
42(10) = 132(5)
Решение - в прилагаемом файле.
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Answers & Comments
Verified answer
1.100(10) = 1100100(2), 350(10) = 101011110(2), 70(10) = 1000110(2)
Решение - в прилагаемом файле.
2.
111(2) = 1*2^2+1*2^1+1*2^0 = 4+2+1 = 7(10)
203(4) = 2*4^2+0*4^1+3*4^0 = 32+3 = 35(10)
150(7) = 1*7^2+5*7^1+0*7^0 = 49+5*7 = 84(10)
3.
101010(2) = 1*2^5+1*2^3+1*2^1 = 32+8+2 = 42(10)
42(10) = 132(5)
Решение - в прилагаемом файле.