㏒²₀,₅x+5㏒₀,₅x-2=0
Пусть㏒₀,₅x=t, тогда
D=25-4*1*(-2)=25+8=33
Делаем обратную замену
㏒₀,₅x=, x=
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Answers & Comments
㏒²₀,₅x+5㏒₀,₅x-2=0
Пусть㏒₀,₅x=t, тогда
D=25-4*1*(-2)=25+8=33
Делаем обратную замену
㏒₀,₅x=
, x=
㏒₀,₅x=
, x=