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Vika123456789001
@Vika123456789001
July 2022
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Помогите решить
(x^2+2x)^2-4(x+1)^2+7=0
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grossman69
Решение на картинке))))
1 votes
Thanks 1
Vika123456789001
а куда делось +7
Vika123456789001
??
армения20171
Х⁴+4х³+4х²-4х²-8х-4+7=0
х⁴+4х³-8х+3=0
х⁴-х³+5х³-5х-3х+3=0
х³(х-1)+5х(х²-1)-3(х-1)=0
(х-1)(х³+5х(х+1)-3)=0
1)х-1=0;х=1
2)х³+5х²+5х-3=0
х³+3х²+2х²+6х-х-3=0
х²(х+3)+2х(х+3)-(х+3)=0
(х+3)(х²+2х-1)=0
х+3=0;х=-3
х²+2х-1=0
Д=1+1=2
х1=-1+√2
х2=-1-√2
ответ 1;-3;-1+√2;-1-√2
2 votes
Thanks 1
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Answers & Comments
х⁴+4х³-8х+3=0
х⁴-х³+5х³-5х-3х+3=0
х³(х-1)+5х(х²-1)-3(х-1)=0
(х-1)(х³+5х(х+1)-3)=0
1)х-1=0;х=1
2)х³+5х²+5х-3=0
х³+3х²+2х²+6х-х-3=0
х²(х+3)+2х(х+3)-(х+3)=0
(х+3)(х²+2х-1)=0
х+3=0;х=-3
х²+2х-1=0
Д=1+1=2
х1=-1+√2
х2=-1-√2
ответ 1;-3;-1+√2;-1-√2