r=0.1 м F=0.1 H q=?
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F=k*q*q/r²
q=r*√(F/k)=0.1*√(0.1/(9*10^9))≈3*10^-7 Кл (0,3 мкКл)
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r=0.1 м F=0.1 H q=?
===
F=k*q*q/r²
q=r*√(F/k)=0.1*√(0.1/(9*10^9))≈3*10^-7 Кл (0,3 мкКл)
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