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artik6984
@artik6984
July 2022
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помогите решить задачу методом интервалов 8 класс плииииз
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nugamanova15
60/(25+х)+60/(25-х)<5
(60*(25+x)+60*(25-x)-5*(25^2-x^2)/(25^2-x^2)<0
(60*50-5*(25^2-x^2))/(25^2-x^2)<0
(600-(25^2-x^2))/(25^2-x^2)<0
(x^2-25)/(25^2-x^2)<0
((x-5)*(x+5))/((25-x)*(25+x))<0
x∈(-5;5)∪(25;+∞)∪(-∞;-25)
Ответ. х∈(-5;5)
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Answers & Comments
(60*(25+x)+60*(25-x)-5*(25^2-x^2)/(25^2-x^2)<0
(60*50-5*(25^2-x^2))/(25^2-x^2)<0
(600-(25^2-x^2))/(25^2-x^2)<0
(x^2-25)/(25^2-x^2)<0
((x-5)*(x+5))/((25-x)*(25+x))<0
x∈(-5;5)∪(25;+∞)∪(-∞;-25)
Ответ. х∈(-5;5)