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nurzhanovasabina1
@nurzhanovasabina1
August 2021
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olgaan980415
BaCl2+Na2SO4=>BaSO4+2NaCl
v(BaCl2)=3.56/270=0.017моль
v(Na2SO4)=3.56/142=0.025моль избыток
3.56--------x
270---------233
x=3.56*233/270=3.07г
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Answers & Comments
v(BaCl2)=3.56/270=0.017моль
v(Na2SO4)=3.56/142=0.025моль избыток
3.56--------x
270---------233
x=3.56*233/270=3.07г