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lergruzimova
@lergruzimova
August 2022
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Помогите решить задачу))
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По теореме Пифагора:
AB²=AC²+CB²=36+64=100
AB=√100=10
A₁B₁²=A₁C₁²+C₁B₁²
C₁B₁²=A₁B₁²-A₁C₁²=625-400=225
C₁B₁=√225=15
8\20=10\25=6\15, значит треугольники подобны.
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Answers & Comments
AB²=AC²+CB²=36+64=100
AB=√100=10
A₁B₁²=A₁C₁²+C₁B₁²
C₁B₁²=A₁B₁²-A₁C₁²=625-400=225
C₁B₁=√225=15
8\20=10\25=6\15, значит треугольники подобны.