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elviravahitova
@elviravahitova
July 2022
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помогите решить задачуууу!!!!
на пружину с коэффициентом упругости о.4 подвесили грузик массой 100 гра. На сколько удлиниться пружина?
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fatt52
Verified answer
M=0.1 кг k=0.4 Н/м x=?
===
F=k*x
F=m*g
x=m*g/k=0.1*10/0.4=2.5 м
===============================
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Answers & Comments
Verified answer
M=0.1 кг k=0.4 Н/м x=?===
F=k*x
F=m*g
x=m*g/k=0.1*10/0.4=2.5 м
===============================