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natasha123456789012
@natasha123456789012
July 2022
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Помогите решить задание из теста))))))))
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oganesbagoyan
Verified answer
4cos²x -3 ≥ 0 ;
4*(1+cos2x)/2 -3
≥ 0 ;
2 +2cos2x -3
≥ 0 ⇔ cos2x
≥ 1/2
2πn
-π/6 ≤ 2x ≤ π/6
+ 2πn ,n∈Z
πn
-π/12 ≤
x ≤ π/12 + πn ,n
∈Z
иначе x ∈[ πn -π/12 ; π/12 + πn ] ,n
∈Z
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oganesbagoyan
Правильный ответ 2. x ∈[ -π/12 + πk ; π/12 + πk ] ,k∈Z
oganesbagoyan
через n или k обозначены целые числа (n∈Z или k∈Z)
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Answers & Comments
Verified answer
4cos²x -3 ≥ 0 ;4*(1+cos2x)/2 -3 ≥ 0 ;
2 +2cos2x -3 ≥ 0 ⇔ cos2x ≥ 1/2
2πn -π/6 ≤ 2x ≤ π/6 + 2πn ,n∈Z
πn -π/12 ≤ x ≤ π/12 + πn ,n∈Z
иначе x ∈[ πn -π/12 ; π/12 + πn ] ,n∈Z