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kiralaitrichter
@kiralaitrichter
August 2022
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Помогите, решить. Задание во вложении
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Aze020
1)9^1-log3(6)
9^1*9^-log3(6)
9*(3^2)^-log3(6)
9*3^-2log3(6)
9*3^log3(6^-2)
9*6^-2
9*1/6^2
9*1/36
1/4
Ответ: 0,25
2)25^1+log5(2)
25^1*25^log5(2)
25*(5^2)^log5(2)
25*5^2log5(2)
25*5^log5(2^2)
25*2^2
25*4
Ответ: 100.
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Answers & Comments
9^1*9^-log3(6)
9*(3^2)^-log3(6)
9*3^-2log3(6)
9*3^log3(6^-2)
9*6^-2
9*1/6^2
9*1/36
1/4
Ответ: 0,25
2)25^1+log5(2)
25^1*25^log5(2)
25*(5^2)^log5(2)
25*5^2log5(2)
25*5^log5(2^2)
25*2^2
25*4
Ответ: 100.