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Kroner
@Kroner
August 2022
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помогите решить значение функции
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snow99
f'(x) =
Xmax = 0
f(0) = 5 --- наибольшее значение
Xmin = 3
f(3) = 1/3 * 3^3 - 3/2 * 3^2 + 5 = 9 - 27/2 + 5 = 14 - 27/2 = 1/2 = 0,5 -- наименьшее значение
f(-1) = 1/3 * (-1)^3 - 3/2 * (-1)^2 + 5 = -1/3 - 3/2 + 5 = -2/6 - 9/6 + 30/6 = 19/6
f(4) = 1/3 * 4^3 - 3/2 * 4^2 + 5 = 64/3 - 24 + 5 = 64/3 - 19 = 7/3
Ответ: 0,5; 5.
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Answers & Comments
f'(x) =
Xmax = 0
f(0) = 5 --- наибольшее значение
Xmin = 3
f(3) = 1/3 * 3^3 - 3/2 * 3^2 + 5 = 9 - 27/2 + 5 = 14 - 27/2 = 1/2 = 0,5 -- наименьшее значение
f(-1) = 1/3 * (-1)^3 - 3/2 * (-1)^2 + 5 = -1/3 - 3/2 + 5 = -2/6 - 9/6 + 30/6 = 19/6
f(4) = 1/3 * 4^3 - 3/2 * 4^2 + 5 = 64/3 - 24 + 5 = 64/3 - 19 = 7/3
Ответ: 0,5; 5.