Помогите решить!!)1) x²-3√2x+4=02)x²+2(1+√8)x+8√2=03) x²-3x-5-√7=0. Created by gulek00. algebra-ru

Помогите решить!!)1) x²-3√2x+4=02)x²+2(1+√8)x+8√2=03) x²-3x-5-√7=0...

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Помогите решить!!)

1) x²-3√2x+4=0
2)x²+2(1+√8)x+8√2=0
3) x²-3x-5-√7=0

Answers & Comments

2407Alexa 1)x²-3√2x+4=0
D=(-3√2)²-4*1*4=18-16=2=√2
x1=(-(-3√2)+√2)/2*1=(3√2+√2)/2=4√2/2
x1=2√2
x2=(-(3√2)-√2)/2=(3√2-√2)/2=2√2/2
x2=√2
2)D=(2+√32)²-4*1*8√2=4+4√32+32-32√2=36+16√2-32√2=(36-16√2)=√(36-22,627)=
=√13,373=3,657
x1=(-(2+2√8)+3,657)/2*1=(-2-2√8+3,657)/2=-1,9999≈-2
x2=(-2-2√8-3,657)/2=(-11,314)/2≈-5,657
3) D=(-3)²-4*1*(-(5-√7)=9+20-4√7=29-4√7=29-10,583=18,417=√18,417≈4,292
x1=(-(-3)+4,292)/2*1=7,292/2
x1≈3,646
x2=(-(-3)-4,292)/2=-1,292/2
x2≈0,646

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