Помогите решить !!!!. Created by daria432824677. algebra-ru

Помогите решить !!!!...

Ответ:

$y(x)=e^{x}\cdot cosx\ \ ,\ \ \ x_0=0\ ,\ dx=0,01\ \ ,\ \ \ \ \boxed{\ dy=y'(x)\cdot dx\ }\\\\\\\boxed{\ (uv)'=u'v+uv'\ }\\\\y'(x)=(e^{x})'\cdot cosx+e^{x}\cdot (cosx)'=e^{x}\cdot cosx-^{x}\cdot sinx=e^{x}\cdot (cosx-sinx)\\\\dy=e^{x}\cdot (cosx-sinx)\cdot dx\\\\\\x=0:\ \ y'(0)=e^0\cdot (cos0-sin0)=1\cdot (1-0)=1\\\\dy\, \Big|_{x=0,dy=0,01}=1\cdot 0,01=0,01$

0 votes Thanks 0

NNNLLL54

Verified answer

Ответ:

e^x(cos x- sin x) dx=e^0(cos 0-sin 0)•0,01= 1(

1-0)•0,01= 0,01

2 votes Thanks 1

Answers & Comments

Verified answer

srochno pomogite reshit dam 41 ball

pomogite reshit dam 35 ballov srochno pozhalujsta

pomogite reshitdam 30 ballovsrochno

рекомендуемые вопросы

Helpful Links

Helpful Social