помогите решите 8,9,10,11 задания по химии
8) 2CH3-OH+2Na=2CH3ONA+ H2
2CH3-COOH+2Mg=2CH3COOMg+H2
9)(C6H10O5)n+nH2O=>n/2 C12H22O11
n/2 C12H22O11 +nH2O=>nC6H12O6
CH3COOH+CH3OH->CH3C=O-OCH3
10)C3H5(OH)3+5O2=3CO2+4H2O
n(C3H5(OH)3)=18,4/92=0,2 моль
n(C3H5(OH)3): n(O2)
1:5
n(O2)=0,2*5=1моль
V(O2)=22,4*1=22.4
11)CH3COOH+CH3CH2OH->C2H5-O-C-(O)-CH3
m(CH3COOH)=100*1.05=105г
n(CH3COOH)=105/60=1,75 моль
n(CH3COOH):n(C2H5-O-C=O-CH3)
1:1
m(C2H5-O-C-(O)-CH3)=1.75*104=182
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коэффициент ² перед кислотой
8) 2CH3-OH+2Na=2CH3ONA+ H2
2CH3-COOH+2Mg=2CH3COOMg+H2
9)(C6H10O5)n+nH2O=>n/2 C12H22O11
n/2 C12H22O11 +nH2O=>nC6H12O6
CH3COOH+CH3OH->CH3C=O-OCH3
10)C3H5(OH)3+5O2=3CO2+4H2O
n(C3H5(OH)3)=18,4/92=0,2 моль
n(C3H5(OH)3): n(O2)
1:5
n(O2)=0,2*5=1моль
V(O2)=22,4*1=22.4
11)CH3COOH+CH3CH2OH->C2H5-O-C-(O)-CH3
m(CH3COOH)=100*1.05=105г
n(CH3COOH)=105/60=1,75 моль
n(CH3COOH):n(C2H5-O-C=O-CH3)
1:1
m(C2H5-O-C-(O)-CH3)=1.75*104=182