помогите... Решите систему. Created by melkii000. algebra-ru

Дана система:.Умножим первое уравнение на 5, второе на -2 и сложим.{10x - 5y = 50,{-10x + 12y² = 8----------------------12y² - 5y = 58.Получили квадратное уравнение:12y² - 5y - 58 = 0.Квадратное уравнение, решаем относительно y: Ищем дискриминант:D=(-5)^2-4*12*(-58)=25-4*12*(-58)=25-48*(-58)=25-(-48*58)=25-(-2784)=25+2784=2809;Дискриминант больше 0, уравнение имеет 2 корня:y₁=(√2809-(-5))/(2*12)=(53-(-5))/(2*12)=(53+5)/(2*12)=58/(2*12)=58/24=29/12 ≈ 2,416667;y₂=(-√2809-(-5))/(2*12)=(-53-(-5))/(2*12)=(-53+5)/(2*12)=-48/(2*12)= -48/24 = -2.x₁ = (10+y₁)/2 = 6 5/24 ≈ 6,208333,x₂ = (10+y₂)/2 = 4.Новые вопросы в АлгебраПЛС М+ПОМОГИТЕ, ДАМС КОРОНУ И МНОГО 30 БАЛЛОВ(Нужно объяснение)557,559 номера. Если возможно,с решением Разложить на множетелиy^8-y^4+4y^2-4Дайте відповідь з рішенням будь ласка(557,559)1) 3 1/9 : 2 1/3 - 2 5/6 =28/9 * 3/7 - 17/6=4/3-17/6= 8/6-17/6=-3/2=-1.5как он получил -3/2Іван зірвав на клумбі 8 нарцисів та 4 тюльпани. Скільки всього існуєспособів вибору із цих квітів 3 нарцисів та 2 тюльпанів для букета?Укажіть функцію, графіком якої є парабола з вершиною у точці О(- 2; 0)Помогите найти решение с описанием ваших действий)Заранее спасибоЗнайдіть область визначення функціїf(x)=2x+4 Сравните числаm+3 и n+3, если m>nПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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melkii000 @melkii000

August 2022 1 16 Report

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Answers & Comments

dnepr1

Verified answer

Дана система:
$\left \{ {{2x-y=10} \atop {5x-6y^2=-4}} \right.$ .
Умножим первое уравнение на 5, второе на -2 и сложим.
{10x - 5y = 50,
{-10x + 12y² = 8
----------------------
12y² - 5y = 58.
Получили квадратное уравнение:
12y² - 5y - 58 = 0.
Квадратное уравнение, решаем относительно y: Ищем дискриминант:
D=(-5)^2-4*12*(-58)=25-4*12*(-58)=25-48*(-58)=25-(-48*58)=25-(-2784)=25+2784=2809;Дискриминант больше 0, уравнение имеет 2 корня:
y₁=(√2809-(-5))/(2*12)=(53-(-5))/(2*12)=(53+5)/(2*12)=58/(2*12)=58/24=29/12 ≈ 2,416667;y₂=(-√2809-(-5))/(2*12)=(-53-(-5))/(2*12)=(-53+5)/(2*12)=-48/(2*12)= -48/24 = -2.
x₁ = (10+y₁)/2 = 6 5/24 ≈ 6,208333,
x₂ = (10+y₂)/2 = 4.