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Lestat97
@Lestat97
July 2022
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Помогите! Решите уравнение
3^2x-1+3^2x=108
2^x+1+2x-1+2^x=28
7^x-7^x-1=6
5^3x+3·5^3x-2=140
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mmb1
Verified answer
3^2x-1+3^2x=108
3^2x-1(1+3)=108
3^(2x-1)=27
3^(2x-1)=3^3
2x-1=3
x=2
2^x+1+2x-1+2^x=28
2^(x-1)(2^2+1+2)=28
2^(x-1)*7=28
2^(x-1)=2^2
x-1=2
x=3
7^x-7^x-1=6
7^(x-1)(7-1)=6
7^(x-1)=1
x-1=0
x=1
5^3x+3·5^3x-2=140
5^(3x-2)(5^2+3)=140
5^(3x-2)*28=140
5^(3x-2)=5
3x-2=1
x=1
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Answers & Comments
Verified answer
3^2x-1+3^2x=1083^2x-1(1+3)=108
3^(2x-1)=27
3^(2x-1)=3^3
2x-1=3
x=2
2^x+1+2x-1+2^x=28
2^(x-1)(2^2+1+2)=28
2^(x-1)*7=28
2^(x-1)=2^2
x-1=2
x=3
7^x-7^x-1=6
7^(x-1)(7-1)=6
7^(x-1)=1
x-1=0
x=1
5^3x+3·5^3x-2=140
5^(3x-2)(5^2+3)=140
5^(3x-2)*28=140
5^(3x-2)=5
3x-2=1
x=1