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NonKogen
@NonKogen
July 2022
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ПОМОГИТЕ! Решите уравнения (подробно с решением) пожалуйста.
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NeZeRAvix
Verified answer
Решение смотри в скане
2 votes
Thanks 0
армения20171
2log(4)2^(4x)=2^(log(³√2)2
2^(4x)>0;x€R
2*1/2 *log(2)2^(4x)=2³
log(2)2^(4x)=8
4x=8
x=2
log(5)(x+1)/10=log(5)2/x
1)ODZ
x>-1;x≠0
2)(x+1)/10=2/x
x≠0
x(x+1)=20
x²+x-20=0
D=1+80=81=9²
x=(-1±9)/2
x1=-5;x2=4
OTBeT 4
1 votes
Thanks 2
армения20171
ODZ x>0
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Answers & Comments
Verified answer
Решение смотри в скане
2^(4x)>0;x€R
2*1/2 *log(2)2^(4x)=2³
log(2)2^(4x)=8
4x=8
x=2
log(5)(x+1)/10=log(5)2/x
1)ODZ
x>-1;x≠0
2)(x+1)/10=2/x
x≠0
x(x+1)=20
x²+x-20=0
D=1+80=81=9²
x=(-1±9)/2
x1=-5;x2=4
OTBeT 4