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Dimon1999A
@Dimon1999A
August 2021
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Помогите решить,пожалуйста: 0,8x4-1,2x^3y+0,8x^2y^2+5,7xy^3-0,9y^4+(-0,1y^4)-2,3x^3y+0,2x^4-0,12x^2y^2-4,2xy^3=? Где ^степень
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Dimon1999A
August 2021 | 0 Ответы
v 3 poselkah 4500 chelovekv pervom v 2 raza menshechem vo vtoromv tretem na 50
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Dimon1999A
August 2021 | 0 Ответы
12a v tretej stepeni 001
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