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Gagarin60
@Gagarin60
July 2022
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dasdasfa
2)4x^2-x≥0; 4x(x-1/4)≥0 + - +
--------------0-------------1/4---------------->x
/////////////// //////////////////////////////
D(y)=(-∞;0]∪[1/4;+∞)
3)x≠2
D(y)=(-∞;2)∪(2;+∞)
0 votes
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Gagarin60
во втором парабола?
dasdasfa
да, парабола
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Answers & Comments
--------------0-------------1/4---------------->x
/////////////// //////////////////////////////
D(y)=(-∞;0]∪[1/4;+∞)
3)x≠2
D(y)=(-∞;2)∪(2;+∞)