Помогите решить.срочно. Created by Tuzffgg. algebra-ru

Помогите решить.срочно...

mikael2 A²-2a-3=(a+1)(a-3) a²-5a+6=(a-3)(a-2)
1/(a+1)(a-3)+1/(a-3)(a-2)=(a-2+a+1)/(a+1)(a-3)(a-2)=(2a-1)/(a+1)(a-3)(a-2)
a(2a-1)-b(2a-1)/a²-a-2=(2a-1)(a-b)/(a−2)(a+1)

(2a-1)(a−2)(a+1)
------------------------------------ = 1/(a-3)(a-b)
(a+1)(a-3)(a-2)(2a-1)(a-b)

0 votes Thanks 2

sedinalana A²-2a-3=(a-3)(a+1)
a1+a2=2 U a1*a2=-3⇒a=-1 U a=3

a²-5a+6=(a-3)(a-2)
a1+a2=5 U a1*a2=6⇒a1=2 U a2=3

2a²-a-2ab+b=a(2a-1)-b(2a-1)=(2a-1)(a-b)

a²-a-2=(a-2)(a+1)
a1+a2=1 U a1*a2=-2⇒a=2 U a=-1
--------------------------------------------------------
1)1/(a-3)(a+1) +1/(a-3)(a-2)=(a-2+a+1)/(a-3)(a+1)(a-2)=
=(2a-1)/(a-3)(a+1)(a-2)
2)(2a-1)/(a-3)(a+1)(a-2) :(a-b)(2a-1)/(a-2)(a+1)=
=(2a-1)/(a-3)(a+1)(a-2) *(a-2)(a+1)/(a-b)(2a-1)=1/(a-b)(a-3)

0 votes Thanks 1

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