Помогите решить,срочно. Created by Grand7Pa. algebra-ru

Помогите решить,срочно...

July 2022 1 3 Report

Помогите решить,срочно

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mami25366 B^(17*3 / 14*5) B^(51/70)
= ------------------------ = ----------------- = B^(51/70 - 7/3) =
B^(7/3) B^(7/3)

1
= B^(153/210 - 490/210) = B^(-337/210) = ------------------- =
B^(337/210)

= $\sqrt[210]{B^3^3^7}$ = $\sqrt[210]{B^2^1^0}$ * $\sqrt[210]{B^1^2^7}$ = B * $\sqrt[210]{B^1^2^7}$

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mami25366 ^ - значок возведения в степень

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