Помогите с 1 и 2 вопросом, пожалуйста!!!. Created by ibragimxalilov2005. matematika-ru

Помогите с 1 и 2 вопросом, пожалуйста!!!...

ibragimxalilov2005 @ibragimxalilov2005

August 2022 1 10 Report

Помогите с 1 и 2 вопросом, пожалуйста!!!

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cooolery

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Пошаговое объяснение:

$1.\\1)\sqrt{225}=\sqrt{15^{2}}=15\\\\ 2)\sqrt{\frac{49}{4}}=\frac{\sqrt{49} }{\sqrt{4} } =\frac{\sqrt{7^{2}} }{\sqrt{2^{2}}}=\frac{7}{2}=3.5\\\\3)\sqrt{6.76}=\sqrt{2.6^{2}}=2.6\\\\ 4)\sqrt{7\frac{1}{9}}=\sqrt{\frac{64}{9}}=\frac{\sqrt{64}}{\sqrt{9}}=\frac{\sqrt{8^{2}} }{\sqrt{3^{2}}}=\frac{8}{3}\\\\ 5)\sqrt{16.81}=\sqrt{4.1^{2}}=4.1\\\\ 6)\sqrt{1225}=\sqrt{35^{2}}=35$

$2.\\1)\sqrt{49} =\sqrt{7^{2}}=7\\ 7\neq -7\\\\2)\sqrt{1.69} =\sqrt{1.3^{2}}=1.3\\1.3\neq -1.3\\\\3)\sqrt{(-9)^{2}}=\sqrt{81}=\sqrt{9^{2}}=9\\ 9\neq -9\\\\4)\sqrt{(-7.8)^{2}}=\sqrt{60.84}=\sqrt{7.8^{2}}=7.8\\ 7.8\neq -7.8$

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pomogite s 1 nomerom i 2a1a5b2a4bfe7680b8ef79358794c3543 64208

pomogite s 17 i 18 nomerom pozhalujsta

zdravstvujte pomogite pozhalujsta s etimi zadaniyami kotorye na foto

pomogite s pervym nomeromb2de4b144cf20bc6923099798fd56d90 42900

pomogite s 15 nomeromfa6de21412fe317d1c4c5341e7f9be73 73001

pomogite pozhalujsta s 6 i 7 nomerom budu lyubezen

pomogite s 17 i 18 pozhalujsta935e1fe2e5e5f389a6833bcd34525366 98225

pomogite s 4 nomerom i 5

pomogite s 4 i 5 pozhalujstab7d38a438d95dc13795d9aad7928e5af 65268

pomogite s 9 i 1033c9538e18ecb9271d10fc0214a3dac8 11670

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