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kolokol800
@kolokol800
August 2022
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помогите с 1 заданием, пожалуйста
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virtualfailikozo0j0
А)1^2+(2-2)^2=1 б)1-4*2=-7
2*1=2 1^2+(3-2)^2=1
1^2=1 -4*2=-8
(2-2)^2=0^2=0 1-8=-7
1+0=1
1^2=1
Да (3-2)^2=1
1+1=2
Нет
1 votes
Thanks 1
virtualfailikozo0j0
Надеюсь понятно
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Answers & Comments
2*1=2 1^2+(3-2)^2=1
1^2=1 -4*2=-8
(2-2)^2=0^2=0 1-8=-7
1+0=1
1^2=1
Да (3-2)^2=1
1+1=2
Нет