Помогите с 33 пожалуйста.. Created by Joker152152. algebra-ru

Помогите с 33 пожалуйста...

Joker152152 @Joker152152

July 2022 1 4 Report

Помогите с 33 пожалуйста.

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sangers1959

Verified answer

Объяснение:

$ax^2-x+1-a$

Неравенство 0<x<1 выглядит следующим образом: x*(x-1)<0. ⇒

$ax^2-x+1-a=x*(x-1)\\ax^2-x+1-a=x^2-x\\ax^2-x^2-a+1=0\\x^2*(a-1)-(a-1)=0\\(a-1)*(x^2-1)=0\\a-1=0\\a=1.$

Ответ: при а=1.

0 votes Thanks 1

Joker152152 Спасибо большое! А каким образом преобразовал неравенство?

sangers1959 x=0 x=1 x*(x-1)=0 ⇒ 0

sangers1959 Неравенство 0

sangers1959 Не даёт объяснить. Далее вторая строчка.

Joker152152 Ок спасибо

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Verified answer

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