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2004255
@2004255
August 2022
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помогите с 5 заданием!!!!!!!!!!!
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CoolSlame
Дано: Решение:
m₁(p-pa)=25г w=m(в-ва)/m(p-pa)
w₁(KCl)=0.2 m₁(KCl)=25г×0.2=5г
m₂(p-pa)=35г m₂(KCl)=35г×0.05=1.75г
w₂(KCl)=0.05 m(KCl)=1.75г+5г=6.75г
w₃(KCl)=? m(p-pa)=25г+35г=60г
w(KCl)=6.75г/60г=0.1125=11.25%
Ответ: w(KCl)=11.25%
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Answers & Comments
m₁(p-pa)=25г w=m(в-ва)/m(p-pa)
w₁(KCl)=0.2 m₁(KCl)=25г×0.2=5г
m₂(p-pa)=35г m₂(KCl)=35г×0.05=1.75г
w₂(KCl)=0.05 m(KCl)=1.75г+5г=6.75г
w₃(KCl)=? m(p-pa)=25г+35г=60г
w(KCl)=6.75г/60г=0.1125=11.25%
Ответ: w(KCl)=11.25%