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Apolinaria2345
@Apolinaria2345
April 2021
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Помогите с 6,7,8 заданием.
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Bronzor1
6) d=3,4, a1=-2,5
An=a1+d*(n-1)=-2,5+3,4*7=-2,5+23,8=21,3
7)
(2/6a+1/6a)*a^2/5=3/6a*a^2/5=3a^2/30a=a/10
a/10=-2,7/10=-0,27
8)
10x>13
x>13/10
x>1,3
x∈(1,3;∞) ответ:4)
2 votes
Thanks 1
sova151
8)4
7)3а/30=3*(-2,7)\30=-0,27
0 votes
Thanks 0
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Answers & Comments
An=a1+d*(n-1)=-2,5+3,4*7=-2,5+23,8=21,3
7)
(2/6a+1/6a)*a^2/5=3/6a*a^2/5=3a^2/30a=a/10
a/10=-2,7/10=-0,27
8)
10x>13
x>13/10
x>1,3
x∈(1,3;∞) ответ:4)
7)3а/30=3*(-2,7)\30=-0,27