a)2y^3-y^2-32y+16=(2y^3-y^2)-(32y+16)=y^2(2y-1)-16(2y-1)=(2y-1)*(y^2-16)=(2y-1)*(y+4)*(y-4)
b)9m^2-3m-n^2+n=(9m^2-n^2)-(3m-n)=(3m-n)*(3m+n)-(3m-n)=(3m-n)*((3m+n)-1)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
a)2y^3-y^2-32y+16=(2y^3-y^2)-(32y+16)=y^2(2y-1)-16(2y-1)=(2y-1)*(y^2-16)=(2y-1)*(y+4)*(y-4)
b)9m^2-3m-n^2+n=(9m^2-n^2)-(3m-n)=(3m-n)*(3m+n)-(3m-n)=(3m-n)*((3m+n)-1)