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NastyaPetrova2k16
@NastyaPetrova2k16
August 2022
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помогите с алгеброй. 7 класс. номера 79(2,3) .76(4,5),77
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79)
2. 15 - (2x² - 4x) - (7x - 2x²) = 0
15 - 2x² + 4x - 7x + 2x² = 0
15 + 4x - 7x = 0
15 - 3x = 0
x = 5 ИЛИ x = 0
3. (y³ + 4y² - 6) - (5y - y³ + 6) = 2y³ + 4y² + y
y³ + 4y² - 6 - 5y + y³ - 6 = 2y³ + 4y² + y
-6 - 6 = 2y³ + 4y² + y - y³ - 4y² +
5y - y³
-12 = y +
5y
-12 = 6y
y = -12
÷ 6
y = -2
76)
4. (13xy - 11x² + 10y²) - (-15x² + 10xy - 15y²) =
=
13xy - 11x² + 10y² + 15x² - 10xy + 15y² =
=
3xy + 4x² + 25y²
5. (14ab² - 17ab + 5a²b) + (20ab - 14a²b) =
= 14ab² - 17ab + 5a²b + 20ab - 14a²b =
=
14ab² + 3ab - 9a²b
77)
1. (a² - b² + c²) - (a² + c² - b²) - (b² - c²) = c² - b²
a² - b² + c² - a² - c² + b² - b² + c²
= c² - b²
-b² + c²
= c² - b²
c² - b²
= c² - b²
2. -a² - (3 - 2a²) + (7a² - 8) - (5 + 8a²) + 16 = 0
-a² - 3 + 2a² + 7a² - 8 - 5 - 8a² + 16 = 0
-a² + 2a² + 7a² - 8a² - 3 - 8 - 5 + 16 = 0
a² + 7a² - 8a² - 11
- 5 + 16 = 0
8a² - 8a² - 16
+ 16 = 0
0
= 0
3. (x³ + 2x²) - (x + 1) - (x² - x) + (4 - x³) = x² + 3
x³ + 2x² - x -
1 - x² + x + 4 - x³ = x² + 3
2x² -
1 - x² + 4 = x² + 3
2x²
- x²
- 1 + 4 = x² + 3
x² + 3
= x² + 3
Не забудьте пометить решение как лучшее!
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Answers & Comments
2. 15 - (2x² - 4x) - (7x - 2x²) = 0
15 - 2x² + 4x - 7x + 2x² = 0
15 + 4x - 7x = 0
15 - 3x = 0
x = 5 ИЛИ x = 0
3. (y³ + 4y² - 6) - (5y - y³ + 6) = 2y³ + 4y² + y
y³ + 4y² - 6 - 5y + y³ - 6 = 2y³ + 4y² + y
-6 - 6 = 2y³ + 4y² + y - y³ - 4y² + 5y - y³
-12 = y + 5y
-12 = 6y
y = -12 ÷ 6
y = -2
76)
4. (13xy - 11x² + 10y²) - (-15x² + 10xy - 15y²) =
= 13xy - 11x² + 10y² + 15x² - 10xy + 15y² =
= 3xy + 4x² + 25y²
5. (14ab² - 17ab + 5a²b) + (20ab - 14a²b) =
= 14ab² - 17ab + 5a²b + 20ab - 14a²b =
= 14ab² + 3ab - 9a²b
77)
1. (a² - b² + c²) - (a² + c² - b²) - (b² - c²) = c² - b²
a² - b² + c² - a² - c² + b² - b² + c² = c² - b²
-b² + c² = c² - b²
c² - b² = c² - b²
2. -a² - (3 - 2a²) + (7a² - 8) - (5 + 8a²) + 16 = 0
-a² - 3 + 2a² + 7a² - 8 - 5 - 8a² + 16 = 0
-a² + 2a² + 7a² - 8a² - 3 - 8 - 5 + 16 = 0
a² + 7a² - 8a² - 11 - 5 + 16 = 0
8a² - 8a² - 16 + 16 = 0
0 = 0
3. (x³ + 2x²) - (x + 1) - (x² - x) + (4 - x³) = x² + 3
x³ + 2x² - x - 1 - x² + x + 4 - x³ = x² + 3
2x² - 1 - x² + 4 = x² + 3
2x² - x² - 1 + 4 = x² + 3
x² + 3 = x² + 3
Не забудьте пометить решение как лучшее!