Помогите с алгеброй пожалуйста. Created by outsider328. algebra-ru

Помогите с алгеброй пожалуйста...

rusbaba2000 7/3 - 2/4 = 28/12 - 6/12= 22/12 = 1 целая 10/12 = 1 целая 5/6
--------------------------------------------------------------
1 1/2 - 2 3/4 = 3/2 - 11/4 = 6/4 - 11/4 = - 5/4 = - 1 целая 1/4
--------------------------------------------------------------
2/8 - 1 3/5=2/8 - 8/5 =10/40-64/40= - 54/40= - 1целая 14/40 = -1целая 7/20

0 votes Thanks 1

nebaura а)

nebaura а)11/6 б)5/4 в)27/20

кляча

Verified answer

А)28/12-6/12=22/12=11/6
б)6/4-11/4=-5/4
в)10/40-64/40=-54/40=-27/20

1 votes Thanks 1

Answers & Comments

Verified answer

itogi krymskoj i potsdamskoj konferencii

vstavte propushennye bukvy2c6d6c9e04eb6c76f3266967bb0e50c8 1231

pomogite s fizikoj pozhalujstad04d0cef1196054d1889fe28bdda9e05 84949

pomogite s geografiejc468b8e5e6df868c464de041792d5f1c 71675

pomogite s algebrojnajdite korni uravneniya 5x215x0

pomogite s algebroj32dd9577ba2729b626156548f526d382 65878

reshit uravneniya 1 15x228 2 2x 73 3 3x40 4 x22x150 5 2x27x0

pomogite s algebroj zaranee spasibo5c53c83f759f582b37b1b7fc944573ea 78183

pomogite s voprosami po biologii88650fa4bfa02e7554442ae26559967e 3575

pomogite s algebroj pozhalujsta952c1309ec56a5c5b06041789eeec99a 20284

рекомендуемые вопросы

Helpful Links

Helpful Social