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natkalove2010
@natkalove2010
August 2022
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помогите с дифиринциалом функции одной переменной
y=sin^3 2x
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GUGHJ
Dy=dxy'
y'=2cosxsinx
y'(π/4)=2cosπ/4*sinπ/4=2*√2/2*√2/2=2*√4/4=√4/2=2/2=1
dy=0,02*1=0,02.
Так?
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Answers & Comments
y'=2cosxsinx
y'(π/4)=2cosπ/4*sinπ/4=2*√2/2*√2/2=2*√4/4=√4/2=2/2=1
dy=0,02*1=0,02.
Так?