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JuliaPancy
@JuliaPancy
August 2022
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Помогите с дз пожалуйста!!
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Godnessgirl
1. f(x)=5x-12 I=[-4;6]
f(-4)=5*(-4)-12=-20-12=-32
f(6)=5*6-12=30-12=18
f(x)min=f(-4)=-32
f(x)max=f(6)=18.
2. f(x)=4-x²+3x
f'(x)=-2x+3
-2x+3=0
-2x=-3
x=-3/(-2)
x=1,5 точка экстремума
f(1,5)=4-1,5²+3*1,5=4-2,25+4,5=6,25.
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JuliaPancy
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Answers & Comments
f(-4)=5*(-4)-12=-20-12=-32
f(6)=5*6-12=30-12=18
f(x)min=f(-4)=-32
f(x)max=f(6)=18.
2. f(x)=4-x²+3x
f'(x)=-2x+3
-2x+3=0
-2x=-3
x=-3/(-2)
x=1,5 точка экстремума
f(1,5)=4-1,5²+3*1,5=4-2,25+4,5=6,25.