1)
Q=mL
Q=3*3.4*10^5=1020 кДж
2) Q=cm(t2-t1)+Lm=m(c(t2-t1)+L)
Q=150(2100*8 + 3.4*10^5)=150*(16800+340000) = 53 520 кДж
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Answers & Comments
1)
Q=mL
Q=3*3.4*10^5=1020 кДж
2) Q=cm(t2-t1)+Lm=m(c(t2-t1)+L)
Q=150(2100*8 + 3.4*10^5)=150*(16800+340000) = 53 520 кДж