Дано:
t1 = 80C°
t2 = 65C°
m = 120 кг
c = 4200
Q =?
∆t = 65-80= -15
Q = m∆tc
Q = 120•(-15)•4200 = -7560000Дж = -7,56МДж
-7,56МДж•24ч = -181,44 МДж
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Q=cm(дельта)t = 15*4200*120= 1260000 Дж : 1000000= 1,26 МДж
Дано:
t1 = 80C°
t2 = 65C°
m = 120 кг
c = 4200
Q =?
∆t = 65-80= -15
Q = m∆tc
Q = 120•(-15)•4200 = -7560000Дж = -7,56МДж
-7,56МДж•24ч = -181,44 МДж