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Lavalik2
@Lavalik2
September 2021
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Помогите с физикой !!!
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columbus70
Дано:
q=-3×10^-7 Кл
F=0,035 Н
E-?
Решение:
E=F/q
E= 0,035Н/-3×10^-7=-116600 Н/Кл= -116,6 Н/кКЛ(килокулон)
E=-116,6 Н/кКл
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Answers & Comments
q=-3×10^-7 Кл
F=0,035 Н
E-?
Решение:
E=F/q
E= 0,035Н/-3×10^-7=-116600 Н/Кл= -116,6 Н/кКЛ(килокулон)
E=-116,6 Н/кКл