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юЛИЯ5gaika
@юЛИЯ5gaika
October 2021
1
7
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помогите с геометрией 6,7,8.
и 1,2.
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maryfine
Verified answer
1. ответ 2)
2. ответ 5)
6. ответ 4)г
7. ответ 2)√220/44
tg²α = (1/(1-sin²α))-1=(1/(1-(5/49)))-1=49/44 - 1=5/44
tgα=√(5/44)=√(5*44/44*44)=√220/44
8. ответ 1)S1>S2
S1=(1/2)*6*6*sin45°=6√2≈8,49
S2=(1/2)*3*5*sin60°=15√3/4≈6,5
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Answers & Comments
Verified answer
1. ответ 2)2. ответ 5)
6. ответ 4)г
7. ответ 2)√220/44
tg²α = (1/(1-sin²α))-1=(1/(1-(5/49)))-1=49/44 - 1=5/44
tgα=√(5/44)=√(5*44/44*44)=√220/44
8. ответ 1)S1>S2
S1=(1/2)*6*6*sin45°=6√2≈8,49
S2=(1/2)*3*5*sin60°=15√3/4≈6,5