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Lalitapriyadd
@Lalitapriyadd
May 2022
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Помогите с геометрией. 8класс
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армения20171
1)7²=5²+8²-2*5*8*cos(<A)
49=25+64-2*5*8cos<A
cos<A=(89-49)/(2*5*8)=1/2
<A=60°
2)S=1/2 *5*8*sin60°=10√3
3)R=abc/4S=5*7*8/40√3=7/√3=7(√3)/3
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Answers & Comments
49=25+64-2*5*8cos<A
cos<A=(89-49)/(2*5*8)=1/2
<A=60°
2)S=1/2 *5*8*sin60°=10√3
3)R=abc/4S=5*7*8/40√3=7/√3=7(√3)/3