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alritepetal
@alritepetal
July 2022
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Помогите с геометрией :)
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oganesbagoyan
Verified answer
3)
<DBC= <ABC/2 =(90° -<BAC)/2 =(90° -36°)/2 =54°/2 =27°.
<BDC =90 -<DBC =90° -27° =63°.
----------------------------------------
4)
AB =BC ⇒ <A=<C .
<A+<С =100°⇒<B =180° -100° =80°.
<A+<A =100 °;
<A =<C =50.
внешние углы :
<A₁ =180° -<A =180° -50° =130° ; или <A₁ = <B +<C =80°+50° =130° .
<С₁= 180° -<С =180° -50° =130°; или <С₁= <B+ <A =80°+50° =130° .
<B₁=180° -<B =180° -80°= 100°. или <B₁ =<A+<C =50°+50° =100°.
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Verified answer
3)<DBC= <ABC/2 =(90° -<BAC)/2 =(90° -36°)/2 =54°/2 =27°.
<BDC =90 -<DBC =90° -27° =63°.
----------------------------------------
4) AB =BC ⇒ <A=<C .
<A+<С =100°⇒<B =180° -100° =80°.
<A+<A =100 °;
<A =<C =50.
внешние углы :
<A₁ =180° -<A =180° -50° =130° ; или <A₁ = <B +<C =80°+50° =130° .
<С₁= 180° -<С =180° -50° =130°; или <С₁= <B+ <A =80°+50° =130° .
<B₁=180° -<B =180° -80°= 100°. или <B₁ =<A+<C =50°+50° =100°.