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teQuiLkaaa
@teQuiLkaaa
July 2022
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Помогите с химией, пожалуйста! Даю 50 баллов
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kojl32tb
Zn+2HCI=ZnCI2 +H2
v(Zn)/v(H2)=1/1
V(zn)=32/65=0,5 моль
v(h2)=0,5 моль
V(H2)=0,5 *22,4 = 11,2
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teQuiLkaaa
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Answers & Comments
v(Zn)/v(H2)=1/1
V(zn)=32/65=0,5 моль
v(h2)=0,5 моль
V(H2)=0,5 *22,4 = 11,2