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TheVladCross
@TheVladCross
August 2022
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BobrovFedor
Б4 а4 б2 в3 г1 Б5 а3 б2 в3
С1 СН4+2О2=СО2+2Н2О
V=2*(12:22,4)*22,4=24 л (4)
С2 m=2*(1,12:22,4)*(24+5+16+23)=6,8 г (2)
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Answers & Comments
С1 СН4+2О2=СО2+2Н2О
V=2*(12:22,4)*22,4=24 л (4)
С2 m=2*(1,12:22,4)*(24+5+16+23)=6,8 г (2)