Ответ:
дано
m(CH3COOH) = 64 g
η(CH3COOCH3) = 80%
-----------------------
m(CH3COOCH3) - ?
Составляем УХР
CH3COOH+CH3OH-->CH3COOCH3+H2O
M(CH3COOH) = 60 g/mol
M(CH3COOCH3) = 74 g/mol
n(CH3COOH) = m(CH3COOH) / M(CH3COOH) = 64 / 60 = 1.07 mol
n(CH3COOH) = n(CH3COOCH3) = 1,07 mol
mтеор (CH3COOCH3) = n(CH3COOCH3) * M(CH3COOCH3) = 1.07 * 74 = 79.18 g
m прак(CH3COOCH3) = mтеор(CH3COOCH3) * η(CH3COOCH3) / 100%
m (CH3COOCH3) = 79.18 * 80% / 100% = 63.344 g
ответ 63.344 г
Объяснение:
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Verified answer
Ответ:
дано
m(CH3COOH) = 64 g
η(CH3COOCH3) = 80%
-----------------------
m(CH3COOCH3) - ?
Составляем УХР
CH3COOH+CH3OH-->CH3COOCH3+H2O
M(CH3COOH) = 60 g/mol
M(CH3COOCH3) = 74 g/mol
n(CH3COOH) = m(CH3COOH) / M(CH3COOH) = 64 / 60 = 1.07 mol
n(CH3COOH) = n(CH3COOCH3) = 1,07 mol
mтеор (CH3COOCH3) = n(CH3COOCH3) * M(CH3COOCH3) = 1.07 * 74 = 79.18 g
m прак(CH3COOCH3) = mтеор(CH3COOCH3) * η(CH3COOCH3) / 100%
m (CH3COOCH3) = 79.18 * 80% / 100% = 63.344 g
ответ 63.344 г
Объяснение: