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юлька426
@юлька426
July 2022
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mozgachik
1. Ответ: 2tgx+С
2. заменяем u=2x ⇒ du=2dx ⇒(1/2)*∫cos(u)du=sin(u)/2;
∫cos(u)du=sin(u);
Ответ: sin(2x)/2
3. ∫(x²+x-16)dx=x³/3+x²/2-16x;
(4³/3+4²/2-16*4)-(1³/3+1²/2-16*1)=283/6.
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Answers & Comments
2. заменяем u=2x ⇒ du=2dx ⇒(1/2)*∫cos(u)du=sin(u)/2;
∫cos(u)du=sin(u);
Ответ: sin(2x)/2
3. ∫(x²+x-16)dx=x³/3+x²/2-16x;
(4³/3+4²/2-16*4)-(1³/3+1²/2-16*1)=283/6.