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ragemd
@ragemd
July 2022
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помогите с математикой
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Rozemey
Verified answer
(2x-9)/5 + (3x+1)/4 ≥ 0
4(2x-9) + 5(3x+1) ≥ 0
8x-36+15x+5 ≥ 0
8x+15x+5-36 ≥ 0
23x-31 ≥ 0
23x ≥ 31
x ≥ 31/23
x ≥ 1 8/23
x∈[1 8/23; +∞)
1 votes
Thanks 1
ragemd
Спасбио , но я ошибся , вместо 9 , 3 в условии
ragemd
можешь написать , но только с 3
товик
ошибка в решении
Rozemey
(2x-3)/5 + (3x+1)/4 ≥ 0
4(2x-3) + 5(3x+1) ≥ 0
8x-12+15x+5 ≥ 0
8x+15x+5-12 ≥ 0
23x-7 ≥ 0
23x ≥ 7
x ≥ 7/23
Rozemey
x∈[7/23; +∞)
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Answers & Comments
Verified answer
(2x-9)/5 + (3x+1)/4 ≥ 04(2x-9) + 5(3x+1) ≥ 0
8x-36+15x+5 ≥ 0
8x+15x+5-36 ≥ 0
23x-31 ≥ 0
23x ≥ 31
x ≥ 31/23
x ≥ 1 8/23
x∈[1 8/23; +∞)
4(2x-3) + 5(3x+1) ≥ 0
8x-12+15x+5 ≥ 0
8x+15x+5-12 ≥ 0
23x-7 ≥ 0
23x ≥ 7
x ≥ 7/23