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andreykadnikov
@andreykadnikov
July 2022
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Помогите с номером 1! Нужно сделать все , кроме г!) Огромное спасибо заранее
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m11m
а)
(x-5)(3 -7x)(2x+4) ≤ 0 ;
-7*2(x+2)(x-3/7)(x-5) ≤0 ;
(x+2)(x-3/7)(x-5) ≥0 ;
методом интервалов :
- + - +
---------- [ -2 ] ---------- [ - 3/7 ] ---------[ 5 ] -----------
x∈ [ -2 ; -3/7 ] U [ 5 ; ∞)
---------------
б
) (x² -5x-6)(7x+11) >0
(x+1)(x-6)*7(x+11/7) >0 ;
(x+11/7)(x+1)(x-6) >0;
- + - +
----------- -11/7 ----- -1 ------- 6 -------
x∈( -11/7 ; -1) U (6 ;∞)
--------------
в)
-5(x-3/5)*2(x²-2x +1+1) <0
(x - 3/5)((x -1)² +1) > 0 ;
x>3/5 .
x∈(3/5 ;∞) .
---------------
г)
(x² -6x -7)(x² +x+1) ≥0 ;
(x+1)(x -7)((x-1/2)² +3/4) ≥0 ;
(x+1)(x -7) ≥0 ;
x∈[-∞;-1} U[7;∞)
1 votes
Thanks 1
oganesbagoyan
15 баллов для всех задач
oganesbagoyan
Verified answer
A) (x-5)(3-7x)(2x+8)≤0
(x-5) * (-7) *(x- ³/₇) * 2 *(x+4)≤0
(x-5)(x-³/₇)(x+4)≥0
x=5 x=³/₇ x= -4
- + - +
--------
-4 ------------ ³/₇
---------------
5 ------------------
\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\
x∈[-4; ³/₇]U[5; +∞)
1 votes
Thanks 1
oganesbagoyan
(x+1)(x -7)((x+1/2)² +3/4) ≥0
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Answers & Comments
а) (x-5)(3 -7x)(2x+4) ≤ 0 ;
-7*2(x+2)(x-3/7)(x-5) ≤0 ;
(x+2)(x-3/7)(x-5) ≥0 ;
методом интервалов :
- + - +
---------- [ -2 ] ---------- [ - 3/7 ] ---------[ 5 ] -----------
x∈ [ -2 ; -3/7 ] U [ 5 ; ∞)
---------------
б) (x² -5x-6)(7x+11) >0
(x+1)(x-6)*7(x+11/7) >0 ;
(x+11/7)(x+1)(x-6) >0;
- + - +
----------- -11/7 ----- -1 ------- 6 -------
x∈( -11/7 ; -1) U (6 ;∞)
--------------
в) -5(x-3/5)*2(x²-2x +1+1) <0
(x - 3/5)((x -1)² +1) > 0 ;
x>3/5 .
x∈(3/5 ;∞) .
---------------
г) (x² -6x -7)(x² +x+1) ≥0 ;
(x+1)(x -7)((x-1/2)² +3/4) ≥0 ;
(x+1)(x -7) ≥0 ;
x∈[-∞;-1} U[7;∞)
Verified answer
A) (x-5)(3-7x)(2x+8)≤0(x-5) * (-7) *(x- ³/₇) * 2 *(x+4)≤0
(x-5)(x-³/₇)(x+4)≥0
x=5 x=³/₇ x= -4
- + - +
-------- -4 ------------ ³/₇ --------------- 5 ------------------
\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\
x∈[-4; ³/₇]U[5; +∞)