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Умница2003
@Умница2003
August 2022
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Помогите с номером 258! Пожалуйста!! Это срочно. Спасибо )
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asa20
(-ab)^4×(2ab)^5=
=-a^4b^4×32a^5b^5=
=32-a^9b^9
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juiva
A) a^4b^4*32a^5b^5
b) (-X)^5y^5*0,001x^9y^6
c) (-1/9)a^4b^8*(-27)a^3b^3
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Answers & Comments
=-a^4b^4×32a^5b^5=
=32-a^9b^9
b) (-X)^5y^5*0,001x^9y^6
c) (-1/9)a^4b^8*(-27)a^3b^3