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Nikol57f
@Nikol57f
July 2022
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Помогите с номером 4, пожалуйста!!
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zhenyaM2002
Verified answer
№4.
a) c(a+b)+2c(2a+3b) =c(a+b +2(2a+3b)) = c(a+b +4a+6b) = c(5a+7b)
б) h(3a-c)+2k(c-3a)= h(3a-c) -2k(3a-c) =(3a-c)(h-2k)
в) (2a+5b)(3c-5d)-(2a+5b)(6c-5d)=(2a+5b)(3c-5d-(6c-5d)) =
= (2a+5b)(3с-5d-6с+5d) = (2a+5b)(-3c)
г) (2а+5b)³(3c-5d)²-(2a+5b)²(6c-5d)³ = (2a+5b)²((2a+5b)(3c-5d)²-(6c-5d)³ )
№5.
2³*5⁴+2⁴*5³ =2³*5³*5¹ +2³*5³*2¹ = 2³*5³*(5¹+2¹)=2³*5³*7=2*2*2*5*5*5*7
5³*7⁵*23 -5³*7⁵*18= 5³*7⁵*(23-18)=5³*7⁵*5 = 5³⁺¹ *7⁵=5⁴*7⁵= 5*5*5*5*7*7*7*7*7
№6.
х(5х-3)+х(2х+11) =0
х(5х-3+2х+11)=0
х(7х+8)=0
произведение=0, если один из множителей =0
х₁=0
7х+8=0
7х=-8
х=-8/7
х=- 1 ¹/₇
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Answers & Comments
Verified answer
№4.a) c(a+b)+2c(2a+3b) =c(a+b +2(2a+3b)) = c(a+b +4a+6b) = c(5a+7b)
б) h(3a-c)+2k(c-3a)= h(3a-c) -2k(3a-c) =(3a-c)(h-2k)
в) (2a+5b)(3c-5d)-(2a+5b)(6c-5d)=(2a+5b)(3c-5d-(6c-5d)) =
= (2a+5b)(3с-5d-6с+5d) = (2a+5b)(-3c)
г) (2а+5b)³(3c-5d)²-(2a+5b)²(6c-5d)³ = (2a+5b)²((2a+5b)(3c-5d)²-(6c-5d)³ )
№5.
2³*5⁴+2⁴*5³ =2³*5³*5¹ +2³*5³*2¹ = 2³*5³*(5¹+2¹)=2³*5³*7=2*2*2*5*5*5*7
5³*7⁵*23 -5³*7⁵*18= 5³*7⁵*(23-18)=5³*7⁵*5 = 5³⁺¹ *7⁵=5⁴*7⁵= 5*5*5*5*7*7*7*7*7
№6.
х(5х-3)+х(2х+11) =0
х(5х-3+2х+11)=0
х(7х+8)=0
произведение=0, если один из множителей =0
х₁=0
7х+8=0
7х=-8
х=-8/7
х=- 1 ¹/₇