1)PbCl4=PbCl2+Cl2
Pb(+4)-2e=Pb(+2) 2. 1
2
2Cl(-1)+2e=Cl2(0) 2. 1
2)2H2S+SO2=3S+2H2O
S(-2)-2e=S(0) 2. 2
S(+4)+4e=S(0) 4. 1
3Cl2+6NaOH=5NaCl+NaClO3+3H2O
Cl2(0)+2e=2Cl(-1). 2. 5
Cl2(0)-10e=2Cl(+5) 10. 1
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Answers & Comments
1)PbCl4=PbCl2+Cl2
Pb(+4)-2e=Pb(+2) 2. 1
2
2Cl(-1)+2e=Cl2(0) 2. 1
2)2H2S+SO2=3S+2H2O
S(-2)-2e=S(0) 2. 2
2
S(+4)+4e=S(0) 4. 1
3Cl2+6NaOH=5NaCl+NaClO3+3H2O
Cl2(0)+2e=2Cl(-1). 2. 5
2
Cl2(0)-10e=2Cl(+5) 10. 1