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kamron971
@kamron971
July 2022
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помогите с решением !sin3x+корень из 3 cos3x <0. (8бал)
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sedinalana
Verified answer
2*(1/2*sin3x+√3/2*cos3x)<0
2*sin(3x+π/3)<0
sin(3x+π/3)<0
π+2πn<3x+π/3<2π+2πn
2π/3+2πn<3x<5π/3+2πn
5π/9+2πn/3<x<5π/9+2πn/3
x∈(5π/9+2πn/3;5π/9+2πn/3,n∈z)
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Answers & Comments
Verified answer
2*(1/2*sin3x+√3/2*cos3x)<02*sin(3x+π/3)<0
sin(3x+π/3)<0
π+2πn<3x+π/3<2π+2πn
2π/3+2πn<3x<5π/3+2πn
5π/9+2πn/3<x<5π/9+2πn/3
x∈(5π/9+2πn/3;5π/9+2πn/3,n∈z)